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OpenStudy (anonymous):
If log(7x+5)/log(2)=1 , then x=
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OpenStudy (zzr0ck3r):
\[\frac{\log(7x+5)}{\log(2)}=1\\\log(7x+5)=\log(2)\] now raise both sides to be powers of what ever the base is.
OpenStudy (zzr0ck3r):
you with me @kmoses24 ?
OpenStudy (anonymous):
I know I am @zzr0ck3r, continue please :P
OpenStudy (zzr0ck3r):
what is the base of the log?
OpenStudy (anonymous):
10 @zzr0ck3r
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