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OpenStudy (anonymous):
find the arc length...y=integral from 1 to x of sqrt(t^3-1) dt. first step i know is finding y prime. wouldn't y prime just be sqrt(x^3-1)?
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OpenStudy (anonymous):
\[y=\int\limits_{1}^{x}\sqrt{t^3-1}dt\] is \[y \prime= \sqrt{x^3-1}\]
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