Question

hey, I tried to run this prog.

x=int(raw_input('enter an integer: '))

ans=0

while ans*ans==x:
ans =ans + 1

print 'the square root of ' + str(x) + 'is' + str(ans)
----------------------------------------

can anyone point out the problem.
the output says the square root of 25 is 0.
of course ill be only entering perfect square roots.

Answer 1

You implemented the increment, but did not put in the decision element necessary to determine if the input has a square root. That decision structure is covered in lecture 3, but here is a crude example to show you what I'm talking about:

x=int(raw_input('enter an integer: '))

ans = 0

while ans*ans < x:
ans = ans + 1
if ans*ans == x:
print 'the square root of ' + str(x) + ' is ' + str(ans)
else:
print 'the square root of ' + str(x) + 'is not an integer'

Note that I did not put in the requisite code to determine a non-integer root (lecture covers that nicely).

Answer 2

@jmike.. i see what i missed.. thank you...

Answer 3

No problem, glad I could help.