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Trigonometry 11 Online
OpenStudy (anonymous):

tan(t)=1/sqrt3

OpenStudy (anonymous):

\[\tan(t)=1/\sqrt3 \rightarrow t= 30^0\] @jdixon1

OpenStudy (anonymous):

The easiest way to think of this is that tan=sin/cos. So using this chart shown, find the where the value of sin or y divided by the value of cos or x equals 1/sqrt3. In this case, its at 30 degrees or pi/6

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