Question

Find an equation of the tangent line to the given curve at the specified point
y= (2x)/(x+1) at (0,0)

Answer 1

I meant (1,1) sorry

Answer 2

first step would be to find the derivative of y:

which gives:\[\frac{ 2 }{ (x+1)^{2} }\]

At (1,1),gradient is \[\frac{ 1 }{ 2 }\]
therefore,we have:
y=mx + c
1=1(1/2) + c
c= 1/2
equation of tangent:
y= (1/2)x + (1/2)