Solve the system by graphing.If the system is inconsistent and has no solution,state this .If the system is dependent,write the form of the solution for any real number x.

y=5x-4
10x-2=6

Question

Solve the system by graphing.If the system is inconsistent and has no solution,state this .If the system is dependent,write the form of the solution for any real number x.

y=5x-4
10x-2=6

anonymous · Answer

hat emath

jack1 · Answer

y = 5x-4    EQN 1
10x-2=6    EQN 2

now there's no y value in equation 2, so x is a constant
10x - 2 = 6
10x       = 8
so  x      = 8/10 = 0.8

does that help @shakur ?

anonymous · Answer

Can you draw the graph of the equation according to the quesition

jack1 · Answer

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anonymous · Answer

According to my solution here is what I got 
y=5x-4
10x-2=6
10x=8 or
x=8/10
y=5(8/10)-4=0

anonymous · Answer

My problem is graphing it in 2 Lines

jack1 · Answer

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this is one of them graphed

jack1 · Answer

y = 5x-4
when y = 0, x = ...?
0 = 5x -4
4 = 5x
x = 4/5 = 0.8

y = 5x-4
when x = 0, y = ...?
y = 5x-4 
y = 5(0)-4
y = -4

u now have 2 points on a straight ling, should be easy to graph
(0, -4)  and (0.8, 0)

jack1 · Answer

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jack1 · Answer

that make sense @shakur ?

anonymous · Answer

can you indicate the number on the point

jack1 · Answer

y = 5x-4
when y = 0, x = ...?
0 = 5x -4
4 = 5x
x = 4/5 = 0.8

y = 5x-4
when x = 0, y = ...?
y = 5x-4 
y = 5(0)-4
y = -4

u now have 2 points on a straight ling, should be easy to graph
$$(0, -4)  and (0.8, 0)$$

jack1 · Answer

points are (x, y) format, i gave them to you above, now you work out which is which... it's not hard dude

anonymous · Answer

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