Question

4cosxsiny=1 what is the differentiation?

Answer 1

product plus chain rule

Answer 2

\[4(\cos(x)\sin(y)y'-\sin(x)\sin(y))=0\]

Answer 3

solve for \(y'\)

Answer 4

\[4\left[ \cos x( \cos y) y' -\sin x \left( \sin y \right)\right]=0\]
\[y'=\frac{ \sin x \sin y }{ \cos x \cos y }=\tan x \tan y \]