Question

how to find the maximum y value of -16x^2+32x+100

Answer 1

max is the second coordinate of the vertex
first coordinate of the vertex is always \(-\frac{b}{2a}\) which in your case is \(-\frac{32}{2\times (-16)}=1\)
second coordinate is what you get if you replace \(x\) by \(1\)

Answer 2

Thanks

Answer 3

yw