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Mathematics 14 Online
OpenStudy (anonymous):

Write using exponents.

OpenStudy (unklerhaukus):

^

OpenStudy (anonymous):

^

OpenStudy (♪chibiterasu):

^

OpenStudy (anonymous):

OpenStudy (♪chibiterasu):

2^2 x^2 3^4 u^69 q^menopause

OpenStudy (♪chibiterasu):

Well first we combine the two Ns which the result is n^2

OpenStudy (anonymous):

C

OpenStudy (anonymous):

only one of the possible answers has \(-3\times 4=-12\) pick that one

OpenStudy (anonymous):

or as @iambatman said, pick C because it is always C everytime C

OpenStudy (♪chibiterasu):

^^ what satellite said

OpenStudy (♪chibiterasu):

C is always the answer, because C is superior to all letters

OpenStudy (anonymous):

ok thank you guys!

OpenStudy (♪chibiterasu):

Q is just an O trying to be fancy with it's little line

OpenStudy (unklerhaukus):

C is for caret

OpenStudy (anonymous):

OpenStudy (♪chibiterasu):

Well I just keep dividing by two until it is undividable with becoming a decimal

OpenStudy (♪chibiterasu):

8/74 4/37 37 is not divisible by 2 so answer is C

OpenStudy (anonymous):

OpenStudy (♪chibiterasu):

What? It' not C?

OpenStudy (♪chibiterasu):

Ok fine it's B

OpenStudy (anonymous):

thank u

OpenStudy (♪chibiterasu):

np

OpenStudy (anonymous):

B for Beaujolais

OpenStudy (♪chibiterasu):

Since when is the answer B not C?

OpenStudy (♪chibiterasu):

satellite you

OpenStudy (anonymous):

oh i thought @UnkleRhaukus said "C for Claret"

OpenStudy (♪chibiterasu):

lel

OpenStudy (anonymous):

OpenStudy (anonymous):

how about this one

OpenStudy (unklerhaukus):

use \[(x^n)^m=x^{nm}\] and \[y^py^q=y^{p+q}\]

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