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Mathematics
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OpenStudy (anonymous):
Write using exponents.
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OpenStudy (unklerhaukus):
^
OpenStudy (anonymous):
^
OpenStudy (♪chibiterasu):
^
OpenStudy (anonymous):
OpenStudy (♪chibiterasu):
2^2
x^2
3^4
u^69
q^menopause
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OpenStudy (♪chibiterasu):
Well first we combine the two Ns which the result is n^2
OpenStudy (anonymous):
C
OpenStudy (anonymous):
only one of the possible answers has \(-3\times 4=-12\) pick that one
OpenStudy (anonymous):
or as @iambatman said, pick C because it is always C everytime C
OpenStudy (♪chibiterasu):
^^ what satellite said
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OpenStudy (♪chibiterasu):
C is always the answer, because C is superior to all letters
OpenStudy (anonymous):
ok thank you guys!
OpenStudy (♪chibiterasu):
Q is just an O trying to be fancy with it's little line
OpenStudy (unklerhaukus):
C is for caret
OpenStudy (anonymous):
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OpenStudy (♪chibiterasu):
Well I just keep dividing by two until it is undividable with becoming a decimal
OpenStudy (♪chibiterasu):
8/74
4/37
37 is not divisible by 2 so answer is C
OpenStudy (anonymous):
OpenStudy (♪chibiterasu):
What? It' not C?
OpenStudy (♪chibiterasu):
Ok fine it's B
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OpenStudy (anonymous):
thank u
OpenStudy (♪chibiterasu):
np
OpenStudy (anonymous):
B for Beaujolais
OpenStudy (♪chibiterasu):
Since when is the answer B not C?
OpenStudy (♪chibiterasu):
satellite you
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OpenStudy (anonymous):
oh i thought @UnkleRhaukus said "C for Claret"
OpenStudy (♪chibiterasu):
lel
OpenStudy (anonymous):
OpenStudy (anonymous):
how about this one
OpenStudy (unklerhaukus):
use
\[(x^n)^m=x^{nm}\]
and
\[y^py^q=y^{p+q}\]
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