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integral of 1/sqrt(2x+1)
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this is equal to:\[\int\limits_{}^{}(2x - 1)^{-1/2} dx\]
yes but how ?
let u = 2x + 1 du = 2 dx \[\frac{ 1 }{ 2 } \int\limits_{}^{} u^{-1/2}du\] integrate and plug u back in
thanks
glad i could help :)
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