Question

integral of x* sqrt(16 - x^2)

Answer 1

This can be written as \[x \left( 16-x ^{2} \right)^{1/2}\]You can use the product rule for this.

Answer 2

how is that ?

Answer 3

uv* int(v)du ??

Answer 4

This might help http://www.mathsrevision.net/product-and-quotient-rules

Answer 5

http://www.numberempire.com/integralcalculator.php?function=sqrt(16-x%5E2)&var=x

Answer 6

let u = 16 - x^2; du = -2x dx

\[-\frac{ 1 }{ 2 } \int\limits_{}^{}u^{1/2} du\]