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Mathematics 11 Online
OpenStudy (anonymous):

How many different three-digit numbers can you form using the digits 1, 2, 3, 4, 5, 6, and 7 without repetition?

OpenStudy (anonymous):

7*6*5 = 210

OpenStudy (shamil98):

There are seven possible digits for the first digit and 6 digits for the second (minus one digit for the digit used as the first digit) and 5 options for the last digit (minus one again for the second digit) and then you just multiply them all together to get a total possible combination of 210 numbers that are possible.

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