Question

Anybody that can help with linear approximations and walk me through it step-by-step?

Answer 1

ask a question

Answer 2

Use linear approximation, i.e. the tangent line, to approximate sqrt64.3 as follows:
Let f(x)= sqrtx The equation of the tangent line to f(x) at x=64 can be written in the form y=mx+b

Answer 3

m=dy/dx which satisfy a point (64,8) you will get an eqn
let say y=sqrtx
dy/dx=1/2sqrtx
at x=64 dy/dx=1/2sqrt64=1/16=m
now when x=64 y=8
8=64/16+b
b=4
y=x/16+4
now put x=64.3

Answer 4

and get y

Answer 5

What do I do after I get y?

Answer 6

that value is approximated value of 64.3