Question

Limit/Trig Question Help Please

Answer 1

\[\lim_{x \rightarrow 0}\frac{ 3\sin ^{2}x }{-1\left( 1-\cos x \right) }=3\lim_{x \rightarrow 0}\frac{ 1-\cos ^{2}x }{ 1-\cos x} \]
\[=3\lim_{x \rightarrow 0}\frac{ \left( 1-\cos x \right)\left( 1+\cos x \right) }{1-\cos x }\]
\[=3\lim_{x \rightarrow 0}\left( 1+\cos x \right)=3\left( 1+\cos 0 \right)=3\left( 1+1 \right)\]
=6

Answer 2

correction
i missed minus.