Question

Am I right?
Multiply.
(4x + 7)2

16x2 + 49 (My Answer)

16x2 + 28x + 49

16x2 + 56x + 49

8x2 + 14

Answer 1

That isn't what I get for an answer.
Recall,

\((ax+b)c=(a\times c)x+bc\)

Answer 2

No, you forgot that (4x+7)(4x+7)
4x x 7 and 7 x 4x.

Answer 3

which is 28x + 28x..

Answer 4

Or is it,

\((4x+7)^2\)

?

Answer 5

Yes that's what it is

Answer 6

The answer is c...
you would only get your answer if the values were (4x-7)^2

Answer 7

That is the value

Answer 8

are you multiplying it by two or are you given the power to two????

Answer 9

Ok,

\((ax+b)^2=(ax+b)(ax+b)\Rightarrow~ax^2+abx+abx+b^2\)

Answer 10

power of 2

Answer 11

And so are the answer chocies

Answer 12

@austinL is right

Answer 13

so is it 16x2 + 28x + 49

Answer 14

No.

Answer 15

So then 16x2 + 56x + 49

Answer 16

So from your question of,

\((4x+7)^2=(4x+7)(4x+7)\Rightarrow~(4x\times4x)+(7\cdot4)x+(7\cdot4)x+(7\cdot7)\)

Answer 17

When simplified,

\(16x^2+56x+49\)

That is correctomundo!

Answer 18

Okay! Thanks for explaining! ^-^

Answer 19

No problem!