Question

Three questions I'm confused on:
P.S THE X2 ARE SQUARED!
1. Let f(x) = x + 7 and g(x) = x - 4. Find f(x) · g(x).

x2 - 3x - 28

x2 - 3x - 11

x2 + 3x - 28

x2 + 3x - 11

2.Let f(x) = x2 + 3x - 4 and g(x) = x + 5. Find f(x) · g(x).

x3 + 3x2 + 16x - 20

x3 + 5x2 + 14x - 20

x3 + 8x2 + 11x - 20

x3 + 9x2 + 19x - 20

Answer 1

3. Let f(x) = 2x2 - 2x + 7 and g(x) = x2 + 9x - 6. Find f(x) - g(x).

x2 - 11x + 13

x2 - 11x + 1

x2 + 7x + 1

x2 + 7x + 13

Answer 2

For the first one I think its either c or d

Answer 3

lol Maths is not luck based blind shooting. Try solving I will correct you if you make a mistake

Answer 4

Okay. X times x = X2+
7-4=3x..Then im lost from there

Answer 5

Wait no, then 7 times 4=28?

Answer 6

x2 + 3x - 28

Answer 7

Yes see you know the stuff!

Answer 8

:) okay, I'll try the next one

Answer 9

so x2+x=x3
then 3x+5x=8x^2
then I know 4 times 5 =20, but I don't know how to get the middle number but i'm pretty sure its x3 + 8x2 + 11x - 20

Answer 10

x2+x is NOT x3
that is true when you multiply x2*x=x3

Answer 11

oh okay

Answer 12

so is x3 + 8x2 + 11x - 20 right?

Answer 13

NO

Answer 14

sry I was looking at the third question

Answer 15

lol that's okay...so were did I mess up on number 2?

Answer 16

I actually looked at it again, and know I think its x3 + 3x2 + 16x - 20

Answer 17

( x2 + 3x - 4)(x + 5) = x2(x+5) +3x(x+5)-4(x+5)
now expand and take all like terns together

Answer 18

I have know idea how to do this.

Answer 19

actually what you said before was correct! go with 8x^2 solution.

Answer 20

OH OKAY :), and the last one I think is x2 - 11x + 1

Answer 21

NO it is A +7-(-6)=+13

Answer 22

So x2 + 7x + 13

Answer 23

option A

Answer 24

oh wait you meant x2 - 11x + 13
Okay! Thanks for all your help!

Answer 25

np :)