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Let W be the width of the table top Then, the length L = W + 2 Area of a rectangle is L*W 15 = L*W 15 = W*(W + 2) 15 = W² + 2W W² + 2W - 15 = 0 @ValentinaT Factor the equation and solve for W. After that, don't forget to add 2 to the value of W to get the L, the length.
So you would get: [3. -5].
W = 3 or W = -5. -5 is extraneous because length in this context cannot be negative. The width of the table is 3. What would the length have to be? @ValentinaT
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