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How to find the length l1 of the mid portion? If given E= 210GPa, total elongation is not exceed 0.2mm, axial load in tension is 150kN.
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Recall that\[E = {\sigma \over \epsilon}\]where\[\sigma = {F \over A}\] and \[\epsilon = {\Delta L \over L}\]Therefore\[E = {F L \over \Delta L A}\]We need to solve for \(L\)
To solve L, it will be like this, 210*10^9 * 0.0002* 22/7*d^2/4 divide 150*10^3?right?
Looks right.
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