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Mathematics 17 Online
OpenStudy (anonymous):

[MEDAL] How to simplify...

OpenStudy (anonymous):

simplify what?

OpenStudy (anonymous):

\[\frac{ \frac{ x+3 }{ 2x-1 } +3}{ 2(\frac{ x+3 }{ 2x-1 })-1 }\]

OpenStudy (anonymous):

hm... fractions in fractions... always nice...

OpenStudy (anonymous):

multiply top and bottom by \(2x-1\) to clear the compound fraction

OpenStudy (anonymous):

use parentheses cancel correctly \[\frac{ \frac{ x+3 }{ 2x-1 } +3}{ 2(\frac{ x+3 }{ 2x-1 })-1 }\times \frac{2x-1}{2x-1}\] is the first step

OpenStudy (anonymous):

Yes I follow

OpenStudy (anonymous):

second step is \[\frac{x+3+3(2x-1)}{2(x+3)-(2x-1)}\]

OpenStudy (anonymous):

third step is remove parentheses using the distributive law combine like terms etc

OpenStudy (anonymous):

So 7x/7 = x Thank you so much!!!

OpenStudy (anonymous):

dis dudes got it down, he types this stuff much faster so i'm just checking over his work. looks correct to me, gj satellite

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