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2 |2x-7| +11 <= 25
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\[2 |2x-7| +11 \le 25\]
First isolate the \(|2x-7|\) part, can you do that?
isolate?
Okay so let \(y=|2x-7|\). Substitute it. \[ 2y+11\leq 25 \]Would you be able to solve for \(y\)?
i guess so.. i'll just transpose 11?
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where did 2x go?
Ummm, just try to get \(y\) by itself.
Well I said \(y=|2x-7|\), so we are ignoring \(x\) for now.
Ignore everything and just solve for \(y\) here. \[ 2y+11\leq 25 \]
\[ 2\color{red}{|2x-7|}+11\leq 25 \to 2\color{red}y+11\leq 25 \]
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ohh.. i see.
Okay can you at least isolate \(y\)?
can i do it later? i need to take my lunch
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