Question

Lebron measured a basketball court and found that the width of the court was 4ft more than half the length. If the perimeter was 288 ft, was was the length and the width of the basketball court?

Answer 1

Does eveeryone agree

Answer 2

one length would be 2L
one width would be L+4
perimeter is 2L +2W
so 2*2L + 2(L+4)
288 = 6L+4
solve for L

Answer 3

What is the perimeter of a rectrangle

Answer 4

(L = a half court length in my example)