Question

solve equation.
-4= 7over33 x
x=132 over 7
x =-132over 7
x=-7over 132
x=-33over28

which equation is and identity
8-(5x+2)=-5x-6
b. 7z+10-z=8z-2(z-5)
c. 8m-4=5m=8-m
d. 6y+5+6y-5

Answer 1

-4=7/33x so we start by multiplying 33x on both sides
-4(33x)=7 then distribute
-132x=7 divide by -132
x=-7/132 C

Answer 2

and can you clarify the 2nd question please

Answer 3

which one is an identity*

Answer 4

ok hold on a bit

Answer 5

an identity means the when the equations on both sides but into their final form, they are identical
so lets look at each answer
a. 8-(5x+2)=-5x-6
8-5x-2=-5x-6
-5x+6=-5x-6 so no
b. 7z+10-z=8z-2(z-5)
6z+10=8z-2z+10
6z+10=6z+10 yes but lets check the others
c. 8m-4=5m=8-m
uhhh?
d. 6y+5+6y-5
this cancels each other and equals 0 so no

Answer 6

so B