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Mathematics 13 Online
OpenStudy (anonymous):

HELP PLEASE

OpenStudy (anonymous):

Solve each system by the addition method. x - 2y = -12 x + 6y = 20 Put your answer in ordered pair (x, y) form.

OpenStudy (anonymous):

with what?

OpenStudy (anonymous):

I can help using substitution method but not sure about addition method

OpenStudy (anonymous):

Any help will do

OpenStudy (anonymous):

are you able to solve the 1st line for x?

OpenStudy (anonymous):

hint, add 2y to both sides to isolate x

OpenStudy (anonymous):

I'm sorry I'm still confused

OpenStudy (anonymous):

x - 2y = -12 +2y +2y ----------------- x = -12 +2y

OpenStudy (anonymous):

replace this new value (-12 +2y) in place of x in the second equation and solve for y

OpenStudy (anonymous):

(-12 +2y) + 6y = 20 now you have 1 variable

OpenStudy (anonymous):

Where did you get the 6y

OpenStudy (anonymous):

-12 +2y +6y = 20 combine like terms (2y and 6y) can you continue it?

OpenStudy (anonymous):

from your second equation x +6y =20 put -12 +2y in place of x

OpenStudy (anonymous):

The addition method is just adding the two equations together (or rather, subtracting them in this case). Just subtract the coefficients like you would individually: x + 6y = 20 - x - 2y = -12 --------------- (1-1)x + (6- -2)y = 20 - -12 0x + 8y = 32 y = 4 Then you can plop that value in and solve for x :)

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