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OpenStudy (anonymous):
Solve each system by the addition method.
x - 2y = -12
x + 6y = 20
Put your answer in ordered pair (x, y) form.
OpenStudy (anonymous):
with what?
OpenStudy (anonymous):
I can help using substitution method but not sure about addition method
OpenStudy (anonymous):
Any help will do
OpenStudy (anonymous):
are you able to solve the 1st line for x?
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OpenStudy (anonymous):
hint, add 2y to both sides to isolate x
OpenStudy (anonymous):
I'm sorry I'm still confused
OpenStudy (anonymous):
x - 2y = -12
+2y +2y
-----------------
x = -12 +2y
OpenStudy (anonymous):
replace this new value (-12 +2y) in place of x in the second equation and solve for y
OpenStudy (anonymous):
(-12 +2y) + 6y = 20
now you have 1 variable
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OpenStudy (anonymous):
Where did you get the 6y
OpenStudy (anonymous):
-12 +2y +6y = 20
combine like terms (2y and 6y)
can you continue it?
OpenStudy (anonymous):
from your second equation x +6y =20
put -12 +2y in place of x
OpenStudy (anonymous):
The addition method is just adding the two equations together (or rather, subtracting them in this case). Just subtract the coefficients like you would individually:
x + 6y = 20
- x - 2y = -12
---------------
(1-1)x + (6- -2)y = 20 - -12
0x + 8y = 32
y = 4
Then you can plop that value in and solve for x :)