Question

Algbera help

Answer 1

\(\bf |x|= -7x+16\\\implies
\begin{cases}
+(x)= -7x+16\implies x = -7x+16\implies x = 2\\ \quad \\
\bf -(x)= -7x+16\implies -x = -7x+16\implies x = -2
\end{cases}\)

x = -2 is EXTRANEOUS or rare or odd, why? because the concept of an absolute value expression, is that its value will always be POSITIVE, is valid btw, just EXTRANEOUS


as far as the other 2

\(\large{ |x-5|=x+2\implies
\begin{cases}
+(x-5)=x+2\\ \quad \\
-(x-5)=x+2
\end{cases}\\ \quad \\ \quad \\
|2x|=x-3\implies
\begin{cases}
+(2x)=x-3\\ \quad \\
-(2x)=x-3
\end{cases}}
\)

Answer 2

hmmm

Answer 3

\(\bf \bf |x|= -7x+16\\\implies
\begin{cases}
+(x)= -7x+16\implies x = -7x+16\implies x = 2\\ \quad \\
\bf -(x)= -7x+16\implies -x = -7x+16\implies x = -\frac{8}{3}
\end{cases}\)

x = \(\bf -\frac{8}{3}\) is EXTRANEOUS or rare or odd, why? because the concept of an absolute value expression, is that its value will always be POSITIVE, is valid btw, just EXTRANEOUS