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OpenStudy (anonymous):
I am doing graphs of functions and relations; need to find the domain and range for x=(y+2)^2
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OpenStudy (ericdl):
domain: [0,∞) range: (-∞,∞)
OpenStudy (anonymous):
to find the domain we make the equation y=? so we squareroot the equation to get y+2=sqrt(x) then subtract 2 y=sqrt(x)-2 do you know what a squareroot function looks like?
OpenStudy (anonymous):
this one is only moved down 2 units
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