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PLEASE HELP! Use the discriminant to determine the number and type of solutions for the following equation. 24x2 – 13 = 0 A. Zero real solutions B. One rational solution C. Two rational solutions D. Two irrational solutions
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The discriminant is b^2 - 4ac. In your problem, a = 24 and b = 0 and c = -13. So, b^2 - 4ac = (0)^2 - 4(24)(-13) = 0 +1248 Since 1248 is greater than 0 but NOT a perfect square, the roots are real, and have irrational solutions.
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