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Find an equation of the line that satisfies the given conditions. y-intercept 2, parallel to the line 2x + 3y + 4 = 0
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so the equation I arrived at is y= (-2/3)x +2 but the software for my assignment says thats wrong.
You have the correct answer in the slope-intercept form. Try to put it in the form Ax + By + C = 0 and see if the software likes it.
3y+2x-6=0?
yeah.
I would put the x term first much like the equation for the other line: 2x + 3y - 6 = 0
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it worked in standard form, i hate mathlab....
Glad it worked.
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