The sum of two numbers is 48. If one third of one number is 5 greater than one sixth of another number, which of the following is the smaller number?

6
22
26
42

please just tell me the answer.

Question

The sum of two numbers is 48. If one third of one number is 5 greater than one sixth of another number, which of the following is the smaller number?

6
22
26
42

please just tell me the answer.

gk99 · Answer

n1 = 48 - n2
1/3 n1 = 1/6n2 + 5

So

1/3 (48-n2) = 1/6n2 + 5
16 - 1/3n2 = 1/6n2 + 5
11 = 1/6n2 + 1/3n2
11 = 1/2n2

n2 = 22

gk99 · Answer

SInce 11 divided by 1/2 is the same as 11 x 2

anonymous · Answer

oh okay thank you.

gk99 · Answer

np! n1 = 26, and n2 is 22, so n2 is (obviously) smaller