Question

Find the value of the discriminant and describe the number and type of roots.
3x2 - 8x + 2 = 0

Answer 1
x2 + 5x + 6 = 0 Answer 2
6x2 -x - 12 = 0



Answer 3
3x2 - 5x + 6 = 0

Answer 4
x2 - 8x +16 = 0

Answer 1

hint :
Discriminant (D) = b^2 - 4ac

see the values of a,b, and c from the quadratic equ :
ax^2 + bx + c = 0

Answer 2

yeaa..n i honestly need more help cause the power point wont come up

Answer 3

1# for you
3x2 - 8x + 2 = 0
here known a = 3, b = -8, and c = 2. therefore the value of
D = b^2 - 4ac = (-8)^2 - 4(3)(2) = 64 - 24 = 40
there are 2 real roots

notice :
if D > 0 then there are 2 real roots
if D = 0 then there is one real root
if D < 0 then there are 2 imaginary roots

Answer 4

ok so would it be D=40, two irrational roots??