Question

GCF of 6a^3b, 4a^2b^2, and 22ab^3

Answer 1

let's see if can we find gcf of 6,4 and 22

it would be 2
now let's put it aside and find gcf of \[a ^{3}b, 4a ^{2}b ^{2},22ab^3 \]

by just seeing it we can take ab common

so we get gcf equal to 2ab

Answer 2

Okay smarty pants...lol
GCF
3x^4, 3x, -30

Answer 3

c'mon you should called me something nice ;) ;)

no gcf because we have two different kinds of terms here..

constant and variables and for gcf we need terms of only one kind.. ;)!

Answer 4

So then what would I write in the box provided?

Answer 5

no gcf.. may be none

Answer 6

The base of a triangle is 3 cm greater than the height. The area is 14 cm^2. Find the height and the length of the base.

Answer 7

okie... here we go..

assume height to be x
from given info
then base is x+3

now we have formula for area as \[A(\Delta)=1/2 \times base \times height\]

by putting given values and values of base and height we obtained we get

\[14=1/2 \times x \times (x+3)\]

multiply both sides by 2 then we get

\[28=x(x+3)\rightarrow x ^{2}+3x-28=0\]

can you solve this quadratic equation?

Answer 8

?????????

Answer 9

I'm truly lost :(

Answer 10

did you understand how we got quadratic equation?

Answer 11

No :'(

Answer 12

c'mon what's there not to understand?

Answer 13

Hmmm...I'm completely lost. Idk if it's because I been looking at these problems ALL DAY :(

Answer 14

c'mon take some rest and come back later.. may be that's the way..