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The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units? (4 points) No, the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y. No, the rectangle cannot have x = 60 and y = 11 because x = 24 + 2y. Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 48. Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 24.
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When the perimeter is 60 and the length is 24, then the width has to be 6, not 11. You can figure out which of the first two statements apply.
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