The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units? (4 points)

No, the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y.
No, the rectangle cannot have x = 60 and y = 11 because x = 24 + 2y.
Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 48.
Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 24.

Question

The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units? (4 points)
 	
	No, the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y.
	No, the rectangle cannot have x = 60 and y = 11 because x = 24 + 2y.
	Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 48.
	Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 24.

anonymous · Answer

When the perimeter is 60 and the length is 24, then the width has to be 6, not 11.
You can figure out which of the first two statements apply.