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Where is the vertex of the parabola? y = x2 + 2x + 1 A. Above the x-axis B. Below the x-axis C. On the x-axis D. On the y-axis
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y = x^2 + 2x + 1 y = (x + 1)^2 y = (x - h)^2 + k y = (x - -1)^2 + 0 Therefore, the vertex is at (h,k) = (-1,0) which means C is the correct answer.
Wait what??? IS it A or C??????
vjordillo, you did + 1 + 1 instead of + 1 - 1 and x^2 + 2x + 1 = (x+1)^2
SOOOOO IS IT A OR C?
It's C. I checked with software just now to see that I am right.
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