Simplify the given expression.
(7 − 3i) • (2 − i)
4 + i
14 + 3i
11 − 13i
14 − 10i
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OpenStudy (anonymous):
So...
We distribute so that...
7 * 2 = 14
7 * i = 7i
then
-3i * 2 = -6i
-3i * -i = 3i?
OpenStudy (anonymous):
then combine like terms...
7i - 6i + 3i = 4i
so 14 + 4i?
OpenStudy (anonymous):
dang that isn't a possible answer :S
terenzreignz (terenzreignz):
You MUST recall that
\[\Large i^2 = -1\]
OpenStudy (anonymous):
wait a minute!
-3i * i = 3i^2 right?
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OpenStudy (anonymous):
right
OpenStudy (anonymous):
7i - 6i + 3i^2...
1i + 3i^2 is idk...
OpenStudy (anonymous):
and i^2 = -1, so you have 3(-1)-13i+14 = -3-13i+14=11-13i
OpenStudy (anonymous):
3(-1)
-3 so 1 -3
-2?
OpenStudy (anonymous):
lol I can't get this xD
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OpenStudy (anonymous):
you're getting your negative numbers wrong.....-7 times i is -7i
OpenStudy (anonymous):
hmm...
7 * 2 = 14
7 * i = 7i
then
-3i * 2 = -6i
-3i * -i = 3i^2
3i^2 is 3(-1) so -3...
14 - 3
11
then 7i - 6 = 1i or i
OpenStudy (anonymous):
>.<
OpenStudy (anonymous):
ohhhhh
OpenStudy (anonymous):
7 * -i
= -7i
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OpenStudy (anonymous):
11 - 13i?
OpenStudy (anonymous):
did i get it :D?
OpenStudy (anonymous):
FOIL First, inside, outside, last
(7)(2)=14
(-3i)(2)=-6i
(7)(-i)=-7i
(-3i)(-i)=3i^2
Combine like terms
3i^2-13i+14
i^2 in imaginary numbers=-1
3(-1)-13i+14=-13i+11 or 11-13i
OpenStudy (anonymous):
you got it!
OpenStudy (anonymous):
Thanks for the help man
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