Question

Put function into standard form:

y=2(x-5)^2+31

Answer 1

(x-5)^2=x^2-10x+25
y=2(x^2-10x+25)+31
y=2x^2-20x+50+31
y=2x^2-20x+81

Answer 2

Thank you @marsss

Answer 3

welcome :)

Answer 4

@marsss can you explain the steps please ? <3 sorry for all the trouble.

Answer 5

\[(x-5)^{2}=x ^{2}-10x+25\]

\[y=2(x ^{2}-10x+25)+31=2*x^2-2*10x+2*25+50\]

does it make sense?

Answer 6

Yeah , thank you again lol.

Answer 7

welcome again (: