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Physics 14 Online
OpenStudy (anonymous):

Please help me with my physics homework. (question attached)

OpenStudy (anonymous):

OpenStudy (anonymous):

The time to reach the balls maximum height is t(height)= v(initial)sin(theta)/g we don't know v(initial) but we can find it from the max height , so h(max) = v(initial)^2sin(theta)^2/2g .

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