Question

Solve the equation:

Answer 1

\[4\sin ^{2}x = 3\]

Answer 2

Use the identity: \[\sin ^{2}x -1 = -\cos(2x)\]

4cos(2x) = 2

cos(2x) = 0.5

\[\cos^{-1} (0.5) = 2x\]

x = \[ \frac{\cos^{-1}(0.5) }{ 2 }\]

Answer 3

oops i forgot the negative

Answer 4

piglet can u helpme onmy question plz?