Question

12y^2=20y

Answer 1

Subtract 20y from both sides first.
Then factor out common factor.

Answer 2

how do i do that

Answer 3

Subtract 20y from both sides first:

12y^2 - 20y = 0
y is present in the first term and also in the second term. So y is a common factor.
Also looking at 12 and 20, we can see 4 goes into both. So 4 is also a common factor.

Pull 4y out and divide each term by 4y

4y(3y - 5) = 0

Therefore 4y = 0 or (3y - 5) = 0

So y = 0 or y = 5/3.

0 and 5/3 are the solutions.