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Mathematics 8 Online
OpenStudy (christos):

Integrals, can you please http://screencast.com/t/gO0foJ0U8rA

OpenStudy (christos):

@ganeshie8

OpenStudy (christos):

@Hero

OpenStudy (christos):

@skullpatrol

hero (hero):

What about it?

OpenStudy (christos):

Do you understand this step @hero ?

hero (hero):

\[\frac{3x}{3x - 2} = \frac{3x - 2 + 2}{3x - 2} = \frac{3x - 2}{3x - 2} + \frac{2}{3x - 2} = 1 + \frac{2}{3x - 2}\]

hero (hero):

Is this what you are referring to?

OpenStudy (christos):

yes thank you for elaborating .

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