Question

I need to find the derivative to 8/sqrt(4+3x)

Answer 1

\[=8\left( 4+3x \right)^{\frac{ -1 }{ 2 }}\]
=\[\frac{ -1 }{ 2 }(8)(4+3x)^{\frac{ -3 }{ 2}}(3)=\frac{ -12 }{ \sqrt[3]{4+3x} }\]