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Decompose (-2x-23)/(2x^2 - 9x -5) into partial fractions
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can you factor 2x^2-9x-5 ?
I'm not good at factoring
would it be (2x+1)(x-5)
yes, good! So now you want to find A and B such that \[ \huge \frac{-2x-23}{(2x+1)(x-5)}=\frac{A}{2x+1}+\frac{B}{x-5} \]
How do I do that?
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Multiply both sides by \(\big (2x+1)(x-5)\). What do we get?
I'm sorry lol but I don't know, I'm confused. Multiply that by what?
@watchmath
multiply each side of the equation by (2x+1)(x-5)
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