What is the solution set of x2 + y2 = 26 and x − y = 6?

{(5, -1), (-5, 1)}

{(1, 5), (5, 1)}

{(-1, 5), (1, -5)}

{(5, -1), (1, -5)}

Question

What is the solution set of x2 + y2 = 26 and x − y = 6?


{(5, -1), (-5, 1)}


{(1, 5), (5, 1)}


{(-1, 5), (1, -5)}


{(5, -1), (1, -5)}

hartnn · Answer

plug in x = y+6 in x^2+y^2 =26
what do u get ?

anonymous · Answer

I don't know?

shamil98 · Answer

If x = y + 6
and the equation is 
$$x^2  + y^2 =26$$

shamil98 · Answer

you substitute what x is equal to in the other equation, and solve for y.

shamil98 · Answer

$$(y+6)^2 + y^2 = 26$$
Solve for y from there.

anonymous · Answer

but I don't know how to do that?

hartnn · Answer

do you know thee formula for $(a+b)^2$ ??

anonymous · Answer

i need help with trying to figure out how to solve it

anonymous · Answer

no i dont

hartnn · Answer

ohhh, sorry then i cannot help you. good luck!

jim_thompson5910 · Answer

solve the second equation for x

x - y = 6

x = 6 + y

x = y + 6

----------------

then plug this into the first equation x^2+y^2 =26

x^2+y^2 =26

(y+6)^2+y^2 =26

y^2 + 12y + 36 + y^2 = 26

y^2 + 12y + 36 + y^2 - 26 = 0

2y^2 + 12y + 10 = 0

2(y^2 + 6y + 5) = 0

y^2 + 6y + 5 = 0

(y+1)(y+5) = 0

I'll let you finish up