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Please do not underestimate any questions :| The potential of two plates of a capacitor are +10V and -10V.The charge on one of the plates is 40C.The capacitance of the capacitor is? A)2F B)4F C) 0.5F D)0.25 F
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I am getting 4F
ok.. how is it 4? the potential difference is 20V.. charge is 40C.. C=q/V => 40/20 = 2F
:O i see okay i thought PD =10 silly me
If the KE of the particle is increased 16 times the percentage change in deBroglie wavelength of the particle is?
|dw:1381642003939:dw|
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