Question

integrals,


Please help me solve this thingy : http://screencast.com/t/p9IkklokqHO

Answer 1

try to put u =cos x
then du = ... ?

Answer 2

Yep, that worked indeed

Answer 3

cool :D
lets see what majdishokri has to say...

Answer 4

SIN(x) = y >>>>>>>> dy/dx= COS(x) >>> dx= COS(X)*dy
\[\int\limits \sin(x)^3*y *dy /sine(x) \]
as well as \[\int\limits \sin(x)^2 *y*dy \]
but sin(x)^2= 1-cos(x)^2
and cos (x)=y
\[\int\limits(1-y^2)*y\]
\[\int\limits y-y^3 dy\]

Answer 5

y^2/2-Y^3/3 then replace y >>>>> y= sin(x)