Question

How to simplify

(x+3 / x-2) + (x+1 / x-1) = 10/3

so I can insert values for -b +/- sqrt (b^2 - 4ac / 2a) a quadratic formula

Answer 1

hi,
\[\frac{ x +3 }{x -2 } + \frac{ x + 1 }{ x -1 } = \frac{ 10 }{ 3 }\]

multiply each term by ( x-2)
\[[(\frac{ x +3 }{ x -2 }) \times ( x-2) ] + [ (\frac{ x +1 }{ x-1}) \times ( x-2) ] = \frac{ 10(x-2) }{ 3}\]

now..
multiply each term by ( x-1)
\[(x + 3)(x -1) + [ (\frac{ (x +1)(x -2) }{ x-1 }) \times ( x-1)] = \frac{ 10(x-2)(x-1) }{ 3 }\]

now...
multiply each term by 3
\[3(x + 3)(x-1) + 3(x +1)(x -2) = 10( x-2 )(x -1)\]

now..
simplify
\[3(x^{2} +2x -3) + 3( x^{2} -x -2 ) = 10(x^{2} -3x +2)\]
\[(3x^{2} +6x -9) + ( 3x^{2} -3x -6 ) = (10x^{2} -30x +20)\]
\[3x^{2} +6x -9+ 3x^{2} -3x -6 = 10x^{2} -30x +20\]\[10x^{2} - 3x^{2} - 3x^{2} -30x -6x +3x +20 +9 +6 = 0\]\[4x^{2} -33x +35 = 0\]

now u can apply the formula..
hope this will help ya!!!

Answer 2

did ya got it ? :)

Answer 3

I get it now, but what will a =
b=
and

c=

be?

Answer 4

a = 4
b = -33
c = 35
but before applying the values , solve the problem by urself and check whether the values r same... :P ....