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Mathematics 14 Online
OpenStudy (anonymous):

10 jewellers sell coins having equal mass, m. If one of the jeweller makes a coin having mass m-1. how can we know which of the 10 jewellers is frauding in one weightage?

OpenStudy (dan815):

OH MY GOODDNESSSSssss

OpenStudy (dan815):

HOW DARE HE CHEATS US

OpenStudy (anonymous):

HAHAHAHA smartass,get me the answer already :p

OpenStudy (dan815):

1 wieghtage seems kind of hard are there any special rules

OpenStudy (anonymous):

nope. gave you all the info i had.

OpenStudy (dan815):

like if we split it into 5 coins on the left and 5 coins on the right, u know that, the one with the less weight will come up |dw:1381686255139:dw|

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