Question

$5,000 is invested in two different accounts yielding 3% and 3.5% interest. The interest earned on the two accounts is $155.

How much money was invested at 3% interest?


$1,000
$3,000
$4,000

got b

Answer 1

hey...
if the amount invested at 3% is "x" then the amount invested at 3.5% is (5000 -x)
so...
\[(x \times \frac{ 3 }{ 100 }) + [ (5000 -x) \times \frac{ 35 }{ 1000 }] = 155\]\[30x + 35(5000 - x) = 155000\]\[-5x = 155000 - 175000\]\[x = \frac{ 20000 }{5 }\]\[x = 4000\]

hope this will help ya !!