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Chemistry 20 Online
OpenStudy (anonymous):

4-(1-methylethyl)-5-(1-methylpropyl)decane

OpenStudy (abb0t):

What about it? lol

OpenStudy (anonymous):

give the correct structure

OpenStudy (abb0t):

The parent chain is decane, meaning C\(_{10}\). Start with that. Can you draw it?

OpenStudy (abb0t):

|dw:1381693329352:dw|

OpenStudy (abb0t):

methyl ethyl is also the same thing as isopropyl, just FYI

OpenStudy (anonymous):

plz understand step wise

OpenStudy (abb0t):

the 4 means there is an isopropyl group C4, and the 5, means there's a methylpropyl (sec butyl)

OpenStudy (abb0t):

on C5

OpenStudy (abb0t):

|dw:1381693560662:dw|

OpenStudy (abb0t):

the groups are where the circles are. Those are C4 and C5

OpenStudy (abb0t):

Do you follow?

OpenStudy (anonymous):

plz another

OpenStudy (abb0t):

Another what? You need to be more specific.

OpenStudy (abb0t):

Draw the group(s) on the chain I drew above. Try it.

OpenStudy (anonymous):

yes

OpenStudy (abb0t):

Yes to what?!

OpenStudy (anonymous):

what is meant by zeroth law of thermodynamics

OpenStudy (abb0t):

Wait, what? You're jumping from organic chemistry to thermodynamics.

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