Question

What is the period of the function \[f(x)=\sin \frac{ 1 }{ 2 }x\]

Answer 1

What is the basic form of a sine function?

Answer 2

\[\frac{ opposite }{ hypotenuse }\]

Answer 3

y = A sin( Bx + C ) + D

B = period divisor for original period of function, so if sine has an original period of \(\bf 2\pi\quad \textit{new period is }\quad \cfrac{2\pi}{B}\)

Answer 4

Thanks!

Answer 5

yw