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Evaluate sin 60° without using a calculator by using ratios in a reference triangle.
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sin 60 degree = sqrt(3)/2
Can you explain how you got to that?
Idk what to do though
the trig function sin is always positive on first and second quadrant look at the circle below
on the second quadrant 60 degree is (-1/2, sqrt(3)/2), so since sin is positive on the second quadrant, we take the point sqrt(3)/2
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remember the faze All Student Take Courses. All means all of the trig functions are positive on the 1st quadrant Student = sin is positive on the 2nd quadrant Take = tan is positive on the third quadrant Courses = cos is positive on the 4th quadrant
Thank you so much ((:
no probs
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