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How can x2 + 3x + 1 = 2x2 + 2x + 3 be set up as a system of equations?
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first subtract (x2 + 3x + 1) -(2x2 + 2x + 3)=0 which equals to -x^2+x-2 = 0
then use Quadratic Formula to -x^2+x-2 to solve for x
let me know if u need more assistance
how do i plug that into the quadratic formula?
ax^2 + bx + c.. the formula is x = [ -b ± sqrt(b^2 - 4ac) ] / 2a
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so y plug 1 to b, -1 to a, -2 to c.. then solve it
okay thank you!
welcome :)
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